WebThe diameter of roller 1.5 m long is 84 cm. If it takes 100 revolutions to level a playground, find the cost of levelling this ground at the rate of 50 paise per square metre. ... The diameter of a roller 120 cm long is 84 cm. If it takes 500 complete revolutions to level a playground, dtermine the cost of levelling it at the rate of 30 paise ... WebJan 19, 2024 · Diameter = d = 84cm Radius = r = d/2 = 42cm Length = l = 120 cm T.S.A of cylinder = 2πrh = 2 x 22/7 x 42 x 120 = 31680 cm² Area levelled by 500 revolution = Area of playground = 500 x 31680cm² = 15840000 cm² [ change into m] = 1584 m² Advertisement Still have questions? Find more answers Ask your question
the diameter of the roller 120 cm long is 84 cm if it takes 500 ...
WebSep 23, 2024 · answered the diameter of a roller 120cm long is 84cm if it takes 500 complete Revolution to level a playground determine the cost of levelling it at the rate of 45 paise per square metre Advertisement Answer 12 people found it helpful Divyasamota Diameter=84cm therefore radius=42cm height=120cm area rolled in 1 revolution=c.s.a WebApr 21, 2024 · The diameter of a roller 120cm long is 84cm. If it takes 500 complete revolutions to level a playground, determine the cost of levelling it at the rate plymouth engineered shapes hopkinsville ky
The diameter of a roller is 84cm and its length is 120cm . It
WebFeb 20, 2024 · The diameter of a roller \\[1.5\\] m long is 84 cm. If it takes 100 revolutions to level this playground, find the cost of levelling this ground at the rate of 50 paise per square meter.. Ans: Hint: First, we will convert the diameter of the roller i... WebJan 7, 2024 · Step-by-step explanation: Given; diameter= 84cm .°. radius= 42cm Height= 120cm Therefore; CSA of a Cylinder= 2pi r h =2 × 22/7 × 42 × 120 =44× 6 × 120 =31680 cm^2 Total area of the play ground = 31680 × 500 =15840000 cm^2 = 1584 m^2 Cost- Rs. 25 for 1 m^2 For 1584 m^2 = 1584 × 25 = Rs. 39600 .°. the cost will be Rs. 39,600/-. Advertisement WebJun 18, 2024 · Best answer. 2r = 84cm. ∴ r = 84/2cm = 42cm. h = 120cm. Area of the playground leveled in one complete revolution = 2 π rh. = 2 × 22/7 × 42 × 120 × 31680cm 2. ∴ Area of the playground = 31680 × 500cm 2. = (31680 x 500)/ (100 x 100)m 2 = 1584m 2. ∴ Cost of leveling @ Rs 25 per square metre = Rs 1584 × 25 = 39600. plymouth eoar login